Question

Электрон движется в вакууме со скоростью 3*10^6 м/с в однородном магнитном поле с магнитной индукцией 0,1 Тл. Чему равна сила, действующая на электрон, если угол между направлениями скорости электрона и линиями магнитной индукции равен 60

Answer 1

Ответ:

Дано:

1.6*10^-19кл*3*10^6м/с *0.1Тл=0.48 *10^-3Н

q=1.6*10^-19Кл где q заряд электрона=1.6*10 в -16 степени Кл

В=0.1 Тл

v=3*10^6 м/с

F-?

Answer 2

Calculation of the Force on an Electron in a Magnetic Field

To calculate the force acting on an electron moving in a magnetic field, we can use the formula for the magnetic force on a charged particle:

F = qvB sin(θ)

Where: - F is the force on the electron - q is the charge of the electron (1.6 x 10^-19 C) - v is the velocity of the electron (3 x 10^6 m/s) - B is the magnetic field strength (0.1 T) - θ is the angle between the velocity of the electron and the direction of the magnetic field

In this case, the angle between the velocity of the electron and the magnetic field lines is given as 60 degrees.

Plugging in the values into the formula, we get:

F = (1.6 x 10^-19 C) x (3 x 10^6 m/s) x (0.1 T) x sin(60°)

Calculating this expression gives us the force acting on the electron.