Question

Энергия конденсатора равна 30 Дж. Если заряд на обкладках этого конденсатора равен 300 мкКл, какова его электроёмкость (в нФ)?

Answer 1

P=p*g*h

h= p/p/g

h воды= 800/1000/10= 0.08 м= 8 см  

h ртути= 800/13500/10= 0,006 м= 0,6 см 

Answer 2

Calculating the Capacitance of the Capacitor

To calculate the capacitance (\(C\)) of the capacitor, we can use the formula:

\[ E = \frac{1}{2}CV^2 \]

Where: - \(E\) = energy stored in the capacitor (given as 30 J) - \(C\) = capacitance - \(V\) = voltage across the capacitor

We can rearrange the formula to solve for \(C\):

\[ C = \frac{2E}{V^2} \]

Given that the charge on the plates of the capacitor is 300 µC, we can calculate the voltage using the formula:

\[ Q = CV \]

Where: - \(Q\) = charge on the plates (given as 300 µC) - \(C\) = capacitance - \(V\) = voltage across the capacitor

Calculation Steps

1. Convert the charge from microcoulombs to coulombs. 2. Use the charge and the given voltage to calculate the capacitance.

Calculation

1. Convert the charge from microcoulombs to coulombs: - \(300 \, \mu C = 300 \times 10^{-6} \, C = 0.0003 \, C\)

2. Use the charge and the given voltage to calculate the capacitance: - \(Q = CV\) - \(0.0003 \, C = C \times V\)

Final Result

The capacitance of the capacitor is 0.0003 / V farads.

Please note that the voltage across the capacitor is required to calculate the capacitance. If the voltage is provided, the calculation can be completed.