Question

1.Какое количество теплоты выделится при остывании воды от 80 °С до 20 °С. Удельная теплоёмкость воды 4200 Дж / (кг · °С). Помогите пжпж

Answer 1

Ответ:

252кДЖ

Объяснение:

Q=cm(t2-t1)

где с - теплоемкость вещества, m - масса, t2-t1 - разность температур

так как в условии массы не дано, то

Q=c(t2-t1)

Q=4200*60

Q=252000=252кДЖ

Answer 2

Calculating Heat Release During Cooling of Water

To calculate the amount of heat released during the cooling of water from 80°C to 20°C, we can use the formula:

Q = mcΔT

Where: - Q = heat released - m = mass of the water - c = specific heat capacity of water - ΔT = change in temperature

Given: - Initial temperature (T1) = 80°C - Final temperature (T2) = 20°C - Specific heat capacity of water (c) = 4200 J/(kg·°C)

First, we need to calculate the change in temperature (ΔT): ΔT = T2 - T1 = 20°C - 80°C = -60°C

The negative sign indicates a decrease in temperature.

Now, we can calculate the heat released (Q): Q = mcΔT

Since the mass of water is not provided, we'll assume a standard mass of 1 kg for this calculation.

Q = (1 kg) * (4200 J/(kg·°C)) * (-60°C)

Let's calculate the value of Q.