Question

Две точки находятся на прямой, вдоль которой распространяется волна со скоростью 50 м/с. Период колебаний Т= 0,05 с, расстояние между точками△у=50 см. Найти разность фаз колебаний в этих точках.

Answer 1

Ответ:

Δφ=126рад

Объяснение:

Δх-50см=0,5м

V=50м/с

Т=0,05с

Δφ-?

1. решение Δφ= 2πΔх/λ
2. где λ=vt-длинна волны
3. Δφ=2πΔх/∪Т=2π*0,5м/50м/с*0,05с=1,26рад

Answer 2

Calculating Phase Difference of Oscillations

To find the phase difference of oscillations between two points on a wave, we can use the formula:

Phase Difference (φ) = 2π * Δx / λ

Where: - Δx = Distance between the two points - λ = Wavelength of the wave

Given: - Speed of the wave (v) = 50 m/s - Period of oscillation (T) = 0.05 s - Distance between the points (Δx) = 50 cm = 0.5 m

First, let's calculate the wavelength (λ) using the formula: v = λ / T

Substitute the given values: 50 = λ / 0.05

Solving for λ: λ = 50 * 0.05 = 2.5 m

Now, we can calculate the phase difference using the formula: Phase Difference (φ) = 2π * Δx / λ

Substitute the values: φ = 2π * 0.5 / 2.5 = π radians

So, the phase difference of oscillations between the two points on the wave is π radians.