Question

1. Тело под действием горизонтальной силы 5H перемещается по гори- зонтальному полу на 20 м. Какая работа совершается этой силой? 2. Камень массой 200 г поднят на высоту в 6м. Какую работу совершила сила тяжести? Чему будет равна работа силы тяжести при падении камня? ​

Answer 1

Ответ:

1. А = 100 Дж

2. А = 12 ДЖ

Объяснение:

1. Дано:

F = 5 Н

S = 20м

Найти:

А - ?

Решение:

А = F * S
A = 5 * 20 = 100 Дж

2. Дано:

m = 200г = 0,2 кг

h = 6м

g = 10 м/с²

Найти:

А - ?

Решение:

А = mgh

А = 0,2 * 10 * 6 = 12 Дж

При падении камня работа силы тяжести станет отрицательной, то есть равной -12 Дж.

Answer 2

Question 1:

The horizontal force of 5H acted on the body and moved it 20 m along the horizontal surface. What work was done by this force?

The work done by the horizontal force of 5H is equal to the product of the force and displacement in the direction of the force. According to the information given: - Force (F) = 5H - Displacement (s) = 20 m - Direction of force is the same as the direction of displacement

By the formula for work (W = F×s), the work done by the force of 5H is: W = F×s = 5H × 20 m = 100 H·m

Question 2:

A stone of mass 200 g was lifted to a height of 6 m. What work was done by the force of gravity? What will be the value of work done by the force of gravity during the fall of the stone?

The work done by the force of gravity during lifting of the stone is equal to the change in potential energy, and the work done during falling is equal in magnitude but opposite in sign. Given: - Mass (m) = 200 g = 0.2 kg - Height (h) = 6 m

Work done by gravity during lifting = Change in potential energy = mгh = 0.2 kg × 10 N/kg × 6 m = 12 J

Work done by gravity during falling = -12 J (work and change in potential energy are negative during falling)