Question

Какое давление производит стол весом 200H,если площадь каждой из четырёх его ножек равна 0,0005 м2. только напишите полное решение

Answer 1

$p=\frac{F}{S}=\frac{F}{4S_1} =\frac{200H}{4\cdot 0,0005m^2} =100000Pa=100kPa$

Answer 2

Calculating the Pressure Exerted by the Table

To calculate the pressure exerted by the table, we can use the formula:

Pressure (P) = Force (F) / Area (A)

Where: - Force (F) = Weight (W) = 200H - Area (A) = 0.0005 m^2 (for each of the four legs)

Calculation Steps

1. Calculate the total force exerted by the table. 2. Calculate the total area over which the force is distributed. 3. Use the formula to find the pressure exerted by the table.

Step 1: Calculate the Total Force Exerted by the Table

The weight of the table is given as 200H.

Step 2: Calculate the Total Area

The area of each leg is given as 0.0005 m^2. Since there are four legs, the total area is 4 * 0.0005 m^2.

Step 3: Use the Formula to Find the Pressure

Now, we can use the formula Pressure (P) = Force (F) / Area (A) to find the pressure exerted by the table.

Calculation

1. Total Force (F) = 200H 2. Total Area (A) = 4 * 0.0005 m^2 = 0.002 m^2 3. Pressure (P) = Total Force (F) / Total Area (A)

Substitute the values: P = 200H / 0.002 m^2

Result

The pressure exerted by the table can be calculated using the given values.