Question

ДАМ 20 БАЛЛОВ!!! С помощью рычага строитель поднимает плиту массой 160 кг. Какую силу он прикладывает к большему плечу рычага длиной 4 м, если меньшее плечо равно 1 м? Ускорение свободного падения принять равным 10m/c^2

Answer 1

Ответ:

261,3 - если g = 9.8

266,66 если g = 10

Объяснение:

F2 = mg = 160 * 10 = 1600 (H)

F1l1 = F2l2; F1 = F2/l1 * l2 = 1600 / 3 * 0.5 = 266.6 (Н)

Answer 2

Calculation of the Force Applied by the Lever

To calculate the force applied by the lever, we can use the principle of moments. The principle of moments states that the sum of the clockwise moments is equal to the sum of the anticlockwise moments.

In this case, the force applied by the builder can be calculated using the formula:

Force x Distance = Load x Distance

Where: - Force is the force applied by the builder (unknown) - Distance is the distance from the force to the fulcrum (4 m) - Load is the weight of the plate (160 kg) - Distance is the distance from the load to the fulcrum (1 m)

Substituting the given values into the formula, we can solve for the force applied by the builder:

Force x 4 m = 160 kg x 1 m

Simplifying the equation:

Force = (160 kg x 1 m) / 4 m

Calculating the force:

Force = 40 kg

Therefore, the builder applies a force of 40 kg to the longer arm of the lever.

Please note that the unit of force should be Newtons (N), not kilograms (kg). The given value of 40 kg should be converted to Newtons by multiplying it by the acceleration due to gravity (10 m/s^2):

Force = 40 kg x 10 m/s^2 = 400 N

So, the builder applies a force of 400 Newtons to the longer arm of the lever.