Question

Два провідники по 12 Ом з'єднанi паралельно і приєднанi до двох послідовно з'єднаних провідників з опорами 34 Ом і 10 Ом. Знайти загальний опір з'єднання. (Дано, схема, формула, розрахунок)​

Answer 1

Ответ:

см фото..................... .

Answer 2

Calculation of Total Resistance in the Given Circuit

To find the total resistance in the given circuit, we need to consider the resistances of the two parallel conductors and the two series-connected conductors.

Let's break down the steps to calculate the total resistance:

1. Calculate the equivalent resistance of the two parallel conductors. 2. Calculate the equivalent resistance of the two series-connected conductors. 3. Calculate the total resistance by adding the equivalent resistances obtained in steps 1 and 2.

Step 1: Equivalent Resistance of the Parallel Conductors

When two resistors are connected in parallel, the equivalent resistance can be calculated using the formula:

1/R_parallel = 1/R1 + 1/R2

In this case, the two parallel conductors have resistances of 12 Ω each. Plugging these values into the formula, we get:

1/R_parallel = 1/12 + 1/12

Simplifying the equation:

1/R_parallel = 2/12

1/R_parallel = 1/6

Therefore, the equivalent resistance of the two parallel conductors is 6 Ω.

Step 2: Equivalent Resistance of the Series-Connected Conductors

When two resistors are connected in series, the equivalent resistance is simply the sum of their individual resistances.

In this case, the two series-connected conductors have resistances of 34 Ω and 10 Ω. Adding these resistances together, we get:

R_series = 34 + 10

R_series = 44 Ω

Therefore, the equivalent resistance of the two series-connected conductors is 44 Ω.

Step 3: Calculation of Total Resistance

To calculate the total resistance, we need to add the equivalent resistances obtained in steps 1 and 2.

Total Resistance = R_parallel + R_series

Total Resistance = 6 + 44

Total Resistance = 50 Ω

Therefore, the total resistance of the given circuit is 50 Ω.

Summary

In summary, the total resistance of the given circuit, which consists of two parallel conductors with resistances of 12 Ω each and two series-connected conductors with resistances of 34 Ω and 10 Ω, is 50 Ω. This calculation was done by finding the equivalent resistance of the parallel conductors and the series-connected conductors, and then adding them together.