Question

Период полураспада изотопа Радона 222 86Rn 3,8 суток. Дано 6,4 × 109 атомов Радона. определите количество нераспавшихся атомов через 19 суток​

Answer 1

Ответ:

N=2*10^8

Объяснение:

Дано:

N0=6,4*10^9

T=3,8 суток

t=19 суток

Надо найти: N-?

Решение:

N=N0*2^(-t/T);

N=(6,4*10^9)*2(-19/3,8)=(6,4*1^9)*2^(-5)=0,2*10^9=2*10^8

Answer 2

Period of Half-Life of Radon-222 Isotope

The period of half-life of the Radon-222 isotope is 3.8 days.

Number of Undecayed Atoms of Radon after 19 Days

To determine the number of undecayed atoms of Radon after 19 days, we can use the formula for radioactive decay:

N(t) = N₀ * (1/2)^(t/T)

Where: - N(t) is the number of undecayed atoms at time t - N₀ is the initial number of atoms - t is the elapsed time - T is the half-life of the isotope

Given that there are 6.4 × 10^9 atoms of Radon initially and the half-life is 3.8 days, we can substitute the values into the formula:

N(19) = (6.4 × 10^9) * (1/2)^(19/3.8)

Calculating this expression will give us the number of undecayed atoms of Radon after 19 days.