Question

Автомобиль двигался со скорость 20м/с, затем происходило торможение с ускорением 4м/с^2. Найдите путь, пройденный автомобилем за 6с после момента начала торможения.

Answer 1

L=V0*t-(a*t^2)/2-перемешение тела при равнозамедленном движение

L=20*6- (4*36)/2=120-72=48м и все

Answer 2

Calculation of the Distance Traveled by the Car

To calculate the distance traveled by the car during the 6 seconds after the start of braking, we need to consider the initial velocity, the acceleration, and the time.

Given: - Initial velocity (u) = 20 m/s - Acceleration (a) = -4 m/s^2 (negative because it represents deceleration) - Time (t) = 6 s

To find the distance (s) traveled by the car, we can use the following kinematic equation:

s = ut + (1/2)at^2

Substituting the given values into the equation:

s = (20 m/s)(6 s) + (1/2)(-4 m/s^2)(6 s)^2

Simplifying the equation:

s = 120 m - 72 m

s = 48 m

Therefore, the car traveled a distance of 48 meters during the 6 seconds after the start of braking.