Question

Найдите жесткость пружины школьного динамометра, если под действием силы 4Н она удлинилась на 8 см.?

Answer 1

F=4 H   x=0.08 м   k=?

F=k*x      k=F/x=4/0.08=50 H/м

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Answer 2

Calculation of the Spring Constant

To find the spring constant of the school dynamometer, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position. Mathematically, this can be expressed as:

F = k * x

Where: - F is the force applied to the spring (4 N in this case) - k is the spring constant (what we need to find) - x is the displacement of the spring (8 cm in this case)

To find the spring constant, we can rearrange the equation:

k = F / x

Substituting the given values:

k = 4 N / 8 cm

Now, we need to convert the displacement from centimeters to meters, as the SI unit for force is Newtons and the SI unit for displacement is meters.

1 cm = 0.01 m

Therefore, the displacement in meters is:

8 cm * 0.01 m/cm = 0.08 m

Substituting the values into the equation:

k = 4 N / 0.08 m

Simplifying the equation:

k = 50 N/m

Therefore, the spring constant of the school dynamometer is 50 N/m.