Question

Два неупругих тела массами 200гр и 300гр движутся навстречу друг другу со скоростями 4м/с каждое. Определить скорости этих тел после удара. (ЗСИ) ПОМОГИТЕ ПОЖАЛУЙСТА ( ​

Answer 1

Ответ:

Скорость тел после удара u = 0.8 м/с.

Объяснение:

Дано:                      СИ

m₁ = 200 г            0,2 кг

m₂ = 300 г            0,3 кг

v₁ = v₂ = 4м/с          4 м/с

удар неупругий

Найти:

u -  скорость тел после удара

Решение:

По теореме сохранения импульса

m₂ · v₂ - m₁ · v₁ = (m₁ + m₂) · u

откуда

$u = \dfrac{m_2\cdot v_2 - m_1\cdot v_1}{m_1 + m_2} =\dfrac{0.3\cdot 4 - 0.2\cdot 4}{0.2 + 0.3} =0.8~(m/s).$

Answer 2

Дано:

m2=300 г =0,3 кг

m1=200 г =0,2 кг

v2=v1=4 м/с

v-?

Решение:

m2v2+m1v1=(m1+m2)v - векторная форма

m2v2-m1v1=(m1+m2)v - проекция на ось

v=m2v2-m1v1/(m1+m2)

v=0,3*4-0,2*4/(0,3+0,2)=0,8 (м/с)

Answer 3

Problem Analysis

We have two objects, one with a mass of 200 grams and the other with a mass of 300 grams, moving towards each other with velocities of 4 m/s each. We need to determine the velocities of these objects after the collision.

Solution

To solve this problem, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

The momentum of an object is given by the product of its mass and velocity. Mathematically, momentum (p) is defined as:

p = m * v

where p is the momentum, m is the mass, and v is the velocity.

Let's denote the velocity of the 200-gram object after the collision as v1 and the velocity of the 300-gram object after the collision as v2.

According to the principle of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision:

m1 * v1 + m2 * v2 = m1 * u1 + m2 * u2

where m1 and m2 are the masses of the objects, v1 and v2 are the velocities of the objects after the collision, and u1 and u2 are the velocities of the objects before the collision.

In this case, the masses of the objects are 200 grams and 300 grams, respectively, and the velocities before the collision are 4 m/s each. Plugging in these values, we get:

(200g * v1) + (300g * v2) = (200g * 4m/s) + (300g * 4m/s)

Simplifying the equation, we have:

200g * v1 + 300g * v2 = 200g * 4m/s + 300g * 4m/s

Now, we can solve this equation to find the values of v1 and v2.

Calculation

Let's calculate the velocities of the objects after the collision.

(200g * v1) + (300g * v2) = (200g * 4m/s) + (300g * 4m/s)

Converting the masses to kilograms:

(0.2kg * v1) + (0.3kg * v2) = (0.2kg * 4m/s) + (0.3kg * 4m/s)

Simplifying the equation:

0.2v1 + 0.3v2 = 0.2 * 4 + 0.3 * 4

0.2v1 + 0.3v2 = 0.8 + 1.2

0.2v1 + 0.3v2 = 2

Now, we have one equation with two variables. We need another equation to solve for v1 and v2.

Additional Information Needed

To solve this problem, we need additional information, such as the coefficient of restitution (e) or any other information about the collision. Without this information, we cannot determine the velocities of the objects after the collision.

Please provide any additional information you have about the collision, such as the coefficient of restitution or any other relevant details, so that we can assist you further.