Question

Длина рычага 2м. на концах рычага уравновешены грузы весом 20 и 140Н найдите плечи рычага

Answer 1

F1*L1=F2*L2 ( L1-первое плечо , L2-второе плечо ) , следует F1/F2=L2/L1 , т.е. 20/140=L2/L1  1/7=L2/L1   ,  значит L2=L/8=2/8= 0,25  , следует L2=2-0,25= 1,75 

Answer 2

Calculating the Length of the Lever Arms

To find the lengths of the lever arms, we can use the formula:

Lever Arm 1 (L1) = (Weight 2 * Lever Arm 2) / (Weight 1 + Weight 2)

Substitute the given values: - Weight 1 = 20 N - Weight 2 = 140 N

Lever Arm 1 (L1) = (140 * 2) / (20 + 140) = 280 / 160 = 1.75 m

Lever Arm 2 (L2) = Total Length - Lever Arm 1 - Total Length = 2 m

Lever Arm 2 (L2) = 2 - 1.75 = 0.25 m

Therefore, the lever arms are: - Lever Arm 1 (L1) = 1.75 m - Lever Arm 2 (L2) = 0.25 m