Question

в алюминиевом чайнике массой 300г нагревается 2л воды от 16 до 100*С какое количество теплоты затрачено на нагревание воды?чайника?

Answer 1

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Answer 2

Calculating the Heat Required to Heat Water in an Aluminum Kettle

To calculate the amount of heat required to heat 2 liters of water from 16°C to 100°C in an aluminum kettle weighing 300g, we can use the formula:

Q = mcΔT

Where: - Q = heat energy - m = mass of the water - c = specific heat capacity of water - ΔT = change in temperature

Calculation Steps:

1. Calculate the mass of the water. 2. Use the specific heat capacity of water to calculate the heat energy required.

Calculation:

1. Calculate the mass of the water: - The density of water is approximately 1g/cm³, so the mass of 2 liters of water is 2000g.

2. Use the specific heat capacity of water to calculate the heat energy required: - The specific heat capacity of water is approximately 4.18 J/g°C. - The change in temperature is 100°C - 16°C = 84°C.

Q = mcΔT Q = 2000g * 4.18 J/g°C * 84°C Q ≈ 705,120 J

Therefore, the amount of heat required to heat 2 liters of water from 16°C to 100°C in an aluminum kettle weighing 300g is approximately 705,120 joules.