Question

При скорости 25 метров в секунду поезд начала тормозить.Чему равна скорость поезда через 5 секунд,если ускорение равна 1,2 м в секунду в квадрате.,как решить то?

Answer 1

V=v0+a*t
У нас поезд тормозит => v=v0-a*t
v=25-1,2*5=25-6=19 м/с
Ответ: скорость поезда через 5 секунд после начала торможения 19 м/с

Answer 2

Problem Analysis

We are given the initial speed of a train, the acceleration, and the time it takes for the train to decelerate. We need to find the final speed of the train after 5 seconds.

Solution

To solve this problem, we can use the equation of motion:

Final velocity (v) = Initial velocity (u) + (Acceleration (a) * Time (t))

Given: - Initial velocity (u) = 25 m/s - Acceleration (a) = 1.2 m/s^2 - Time (t) = 5 seconds

Substituting the given values into the equation, we can calculate the final velocity:

v = u + (a * t)

v = 25 + (1.2 * 5)

v = 25 + 6

v = 31 m/s

Therefore, the final velocity of the train after 5 seconds of deceleration is 31 m/s.