Question

Задача Мідну монету, масою 20 г нагріли в окропі. Яка кількість теплоти пішла на нагрівання монети, якщо її температура збільшилася від 22 до 82 градусів?

Answer 1

Ответ:

Объяснение:

Дано:

m=0,02кг

∆t=82-22=60°C

c=380Дж/кг°С

Q-?

Q=cm∆t=380*0,02*60=456Дж

Answer 2

Problem Analysis

To find the amount of heat absorbed by the copper coin, we can use the formula:

Q = mcΔT

Where: - Q is the amount of heat absorbed (in joules) - m is the mass of the coin (in grams) - c is the specific heat capacity of copper (in J/g°C) - ΔT is the change in temperature (in °C)

We are given: - m = 20 g (mass of the coin) - ΔT = 82°C - 22°C = 60°C (change in temperature)

We need to find Q, the amount of heat absorbed.

Specific Heat Capacity of Copper

To find the specific heat capacity of copper (c), we can refer to search results.

According to the search results, the specific heat capacity of copper is approximately 0.39 J/g°C [[1]].

Calculation

Using the formula Q = mcΔT and the given values, we can calculate the amount of heat absorbed by the copper coin.

Q = (20 g) * (0.39 J/g°C) * (60°C)

Calculating this expression, we find:

Q = 468 J

Therefore, the amount of heat absorbed by the copper coin is 468 joules.

Conclusion

The amount of heat absorbed by the copper coin, when its temperature increased from 22°C to 82°C, is approximately 468 joules.