Question

На сколько градусов нагреется 0,2 кг воды, если ей передать 10 Дж теплоты?

Answer 1

Q=cm∆t
c воды=4200Дж/кг* С
10=4200*0,2*∆t
∆t=10/840
∆t=0,01C

Answer 2

Calculating the Temperature Change of Water

To calculate the temperature change of 0.2 kg of water when 10 J of heat is transferred to it, we can use the formula:

Q = mcΔT

Where: - Q = heat energy transferred (in joules) - m = mass of the substance (in kilograms) - c = specific heat capacity of the substance (in J/kg°C) - ΔT = change in temperature (in °C)

We can rearrange the formula to solve for ΔT:

ΔT = Q / (mc)

Substitute the given values: - Q = 10 J - m = 0.2 kg - c = specific heat capacity of water (approximately 4200 J/kg°C)

ΔT = 10 / (0.2 * 4200)

ΔT ≈ 10 / 840 ≈ 0.0119°C

So, the temperature of 0.2 kg of water will increase by approximately 0.0119°C when 10 J of heat is transferred to it.