Question

Тело массой 100 г брошено вертикально вверх с начальной скоростью 20 м/с. Чему равна сила сопротивления, действующая на тело, если через 1 с скорость равна 5 м/c?

Answer 1

M*g + Fc = m*a
a = (v - v₀) / t = (5 м/с - 20 м/с) / 1 с = - 15 м/с²
Fc = m*a - m*g = m*(a - g)
Fc = 0,100 кг * (15 м/с² - 10 м/с²) = 0,5 Н

Answer 2

Calculation of the Resistance Force

To calculate the resistance force acting on the body, we need to use the equation for the net force acting on the body. The net force is equal to the mass of the body multiplied by its acceleration. In this case, the body is moving vertically, so the acceleration is equal to the change in velocity divided by the change in time.

Given: - Mass of the body (m) = 100 g = 0.1 kg - Initial velocity (v0) = 20 m/s - Final velocity (v) = 5 m/s - Time interval (t) = 1 s

The acceleration (a) can be calculated using the formula:

a = (v - v0) / t Substituting the given values:

a = (5 m/s - 20 m/s) / 1 s = -15 m/s^2

The negative sign indicates that the body is decelerating.

Now, we can calculate the net force (F_net) using the formula:

F_net = m * a Substituting the values:

F_net = 0.1 kg * (-15 m/s^2) = -1.5 N

The negative sign indicates that the net force is acting in the opposite direction to the motion of the body.

Since the resistance force (F_resistance) is equal in magnitude but opposite in direction to the net force, we can conclude that:

F_resistance = 1.5 N

Therefore, the resistance force acting on the body is 1.5 N.