Question

Капля дождя массой 0,3г движется со скоростью 3 м/с на высоте 300 м. а) Вычислите потенциальную энергию, которой обладает капля   b) Определите кинетическую энергию капли.    Помогите,пожалуйста!!​

Answer 1

Ответ:

Объяснение:

Ap = mgh

Ak = mv^2/2

m = 0.00003Кг

A = 300*10*0.00003 = 0.03Дж

A = 0.00003*9/2 = 0,000135Дж

Answer 2

Calculation of Potential Energy

To calculate the potential energy of the raindrop, we can use the formula:

Potential Energy = mass * gravitational acceleration * height

Given: - Mass of the raindrop = 0.3 g = 0.3 * 10^-3 kg (1 g = 10^-3 kg) - Gravitational acceleration = 9.8 m/s^2 (approximately) - Height = 300 m

Using the given values, we can calculate the potential energy as follows:

Potential Energy = 0.3 * 10^-3 kg * 9.8 m/s^2 * 300 m

Let's calculate the potential energy:

Potential Energy = 0.3 * 10^-3 * 9.8 * 300 J

The potential energy of the raindrop is 8.82 J.

Calculation of Kinetic Energy

To calculate the kinetic energy of the raindrop, we can use the formula:

Kinetic Energy = 0.5 * mass * velocity^2

Given: - Mass of the raindrop = 0.3 g = 0.3 * 10^-3 kg (1 g = 10^-3 kg) - Velocity = 3 m/s

Using the given values, we can calculate the kinetic energy as follows:

Kinetic Energy = 0.5 * 0.3 * 10^-3 kg * (3 m/s)^2

Let's calculate the kinetic energy:

Kinetic Energy = 0.5 * 0.3 * 10^-3 * 9 J

The kinetic energy of the raindrop is 1.35 * 10^-3 J.

Therefore, the potential energy of the raindrop is 8.82 J, and the kinetic energy is 1.35 * 10^-3 J.