Question

Літак летить горизонтально зі швидкістю 360 км/год на висоті 122 м. Коли він пролітає над деякою точкою поверхні Землі, з нього скидають вантаж. На якій відстані від цієї точки вантаж упаде на Землю? Опором повітря знехтуйте.

Answer 1

Ответ: 1245м

Объяснение:

Скорость свободного падения ≈9.8м/с

Тоисть груз упадёт за 12.45с

360/3600=0.1км/с

12.45*0.1= 1.245км (1245м)

Answer 2

To calculate the distance at which the cargo will fall to the ground when dropped from an airplane flying horizontally at a speed of 360 km/h at an altitude of 122 m, we can use the equations of motion. We will neglect air resistance, as stated in the question.

Initial Analysis

Let's break down the problem and identify the key variables: - Initial speed of the cargo: The cargo is initially moving horizontally with the same speed as the airplane, which is 360 km/h. - Initial height of the cargo: The cargo is dropped from an altitude of 122 m above the ground. - Acceleration due to gravity: The cargo will experience a constant downward acceleration due to gravity, which is approximately 9.8 m/s².

Calculating Time of Flight

To determine the time it takes for the cargo to fall to the ground, we can use the equation of motion for vertical motion:

h = ut + (1/2)gt²

Where: - h is the initial height of the cargo (122 m) - u is the initial vertical velocity of the cargo (0 m/s, as it is dropped) - g is the acceleration due to gravity (-9.8 m/s²) - t is the time of flight

Simplifying the equation, we get:

h = (1/2)gt²

Rearranging the equation to solve for t, we have:

t = sqrt((2h)/g)

Substituting the values, we get:

t = sqrt((2 * 122) / 9.8) ≈ 5.02 seconds

Therefore, it takes approximately 5.02 seconds for the cargo to fall to the ground.

Calculating Horizontal Distance

To calculate the horizontal distance traveled by the cargo during this time, we can use the equation of motion for horizontal motion:

s = ut

Where: - s is the horizontal distance traveled by the cargo - u is the initial horizontal velocity of the cargo (360 km/h) - t is the time of flight (5.02 seconds)

Converting the initial horizontal velocity from km/h to m/s:

u = (360 km/h) * (1000 m/km) / (3600 s/h) ≈ 100 m/s

Substituting the values, we get:

s = (100 m/s) * (5.02 s) ≈ 502 m

Therefore, the cargo will fall to the ground at a horizontal distance of approximately 502 meters from the point it was dropped.

Please note that this calculation neglects air resistance, as stated in the question. In reality, air resistance would have a small effect on the horizontal distance traveled by the cargo.