Question

5 резистов 2 ом 3 ом 10 ом 15 ом 30 ом соединены параллельно к источнику тока ЭДС=90 и внутреннемм сопротивленеем1/31 ома .найти силы токов через резистры

Answer 1

Ответ:

R(5)=1/(1/2+1/3+1/10+1/15+1/30)=30/31 Ом, Ro= R(5)+r=1 Ом, I=U/Ro= 90/1=90 A, U(5)=90*30/31 В,

I1=U(5)/R1=90*30/(31*2)=...A

I2=90*30/(31*3)=.... A

I3=90*30/(31*10)=

I4=90*30/(31*15)=...

I5=90*30/(31*30)=....A

Answer 2

Calculation of Currents through Resistors in Parallel

To find the currents through the resistors in parallel, we need to use Ohm's Law and the rules for calculating currents in parallel circuits.

Let's denote the resistors as R1, R2, R3, R4, and R5, with resistance values of 2 Ω, 3 Ω, 10 Ω, 15 Ω, and 30 Ω, respectively. The total electromotive force (EMF) of the source is 90 V, and the internal resistance of the source is 1/31 Ω.

Calculating the Equivalent Resistance

To calculate the currents through the resistors, we first need to determine the equivalent resistance of the parallel combination. The formula for calculating the equivalent resistance of resistors in parallel is:

1/Req = 1/R1 + 1/R2 + 1/R3 + 1/R4 + 1/R5

Substituting the given resistance values, we have:

1/Req = 1/2 + 1/3 + 1/10 + 1/15 + 1/30

Simplifying the equation:

1/Req = 15/30 + 10/30 + 3/30 + 2/30 + 1/30

1/Req = 31/30

Taking the reciprocal of both sides:

Req = 30/31 Ω

Therefore, the equivalent resistance of the parallel combination is 30/31 Ω.

Calculating the Total Current

To calculate the total current flowing through the circuit, we can use Ohm's Law:

I = V / R

Where I is the current, V is the voltage, and R is the resistance.

The total current can be calculated as:

I_total = EMF / (Req + internal resistance)

Substituting the given values:

I_total = 90 V / (30/31 Ω + 1/31 Ω)

Simplifying the equation:

I_total = 90 V / (31/31 Ω)

I_total = 90 V / 1 Ω

I_total = 90 A

Therefore, the total current flowing through the circuit is 90 A.

Calculating the Currents through the Resistors

To calculate the currents through the individual resistors, we can use the formula:

I_resistor = I_total * (1 / R_resistor)

Substituting the given resistance values, we have:

I_R1 = 90 A * (1 / 2 Ω) = 45 A

I_R2 = 90 A * (1 / 3 Ω) = 30 A

I_R3 = 90 A * (1 / 10 Ω) = 9 A

I_R4 = 90 A * (1 / 15 Ω) = 6 A

I_R5 = 90 A * (1 / 30 Ω) = 3 A

Therefore, the currents through the resistors are as follows: - I_R1 = 45 A - I_R2 = 30 A - I_R3 = 9 A - I_R4 = 6 A - I_R5 = 3 A

Please note that these calculations assume an ideal circuit with no other factors affecting the current flow.