Question

На нагревание кирпича от 20 до 85 с затрачено такое же количество теплоты как для нагревания воды такой же массы на 13 с. Найти удельную теплоемкость кирпича​

Answer 1

Ответ:

c(к) = 840 Дж / (кг * °С)

Объяснение:

Q = c(к)mΔt₁

Q = c(в)mΔt₂

⇒ c(к)mΔt₁ = c(в)mΔt₂

⇒ c(к) = c(в)mΔt₂ / mΔt₁ = (c(в)Δt₂) / Δt₁

c(в) = 4200 Дж / (кг * °С)

Δt₂ = 13 °С

Δt₁ = 85 °С - 20 °С = 65 °С

c(к) = (4200 * 13) / 65 = 840 Дж / (кг * °С)

Answer 2

Calculation of Specific Heat Capacity of Brick

To find the specific heat capacity of the brick, we can use the equation:

Q = mcΔT

Where: - Q is the amount of heat transferred - m is the mass of the substance - c is the specific heat capacity of the substance - ΔT is the change in temperature

In this case, we know that the amount of heat required to heat the brick from 20°C to 85°C is the same as the amount of heat required to heat the same mass of water by 13°C.

Let's assume the mass of the brick and the water is the same, so we can cancel out the mass term in the equation.

Therefore, we have:

Q_brick = Q_water

mcΔT_brick = mcΔT_water

c_brickΔT_brick = c_waterΔT_water

Since we know ΔT_brick = 85°C - 20°C = 65°C and ΔT_water = 13°C, we can rearrange the equation to solve for the specific heat capacity of the brick (c_brick):

c_brick = (c_water * ΔT_water) / ΔT_brick

Now, let's calculate the specific heat capacity of the brick using the given information.

Using the equation above, we can substitute the values:

c_brick = (c_water * 13°C) / 65°C

Unfortunately, the specific heat capacity of water (c_water) is not provided in the question. Without this information, we cannot calculate the specific heat capacity of the brick accurately.

Please provide the specific heat capacity of water (c_water) so that we can proceed with the calculation.