Question

Помогите решить задачу по физике, пожалуйста! Газ в цилиндре увеличился в объеме на 0,004 м3. При этом давление газа было постоянным и равным 2*105 Па. Какую работу совершил газ в течение этого процесса?

Answer 1

Ответ:

800 Дж

Объяснение:

ΔV=0.004 м³    p=2*10^5 Па    A=?

===

p=const

A=p*ΔV=2*10^5*0.004=800 Дж

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Answer 2

Calculation of Work Done by the Gas

To calculate the work done by the gas during this process, we can use the formula:

Work (W) = Pressure (P) * Change in Volume (ΔV)

In this case, the change in volume is given as 0.004 m^3 and the pressure is constant at 2 * 10^5 Pa. Plugging these values into the formula, we can calculate the work done by the gas.

W = (2 * 10^5 Pa) * (0.004 m^3)

Calculating this expression gives us the work done by the gas during the process.

Please note that the units of work are Joules (J).

Let's calculate it:

W = (2 * 10^5 Pa) * (0.004 m^3) = 800 J

Therefore, the gas has done 800 Joules of work during this process.