Question

СРОЧНО!!!! ОТДАЮ ПОСЛЕДНИИ БАЛЫ!!!!!!!!!! 2. Найти силу упругости, которая действует со стороны каната на взбирающегося человека, если, имея жесткость 50 кН/м, канат удлинился на 16 мм.3. Какая сила тяжести действует на кувшин с медом, если масса самого кувшина 0.4 кг, мёд в него перелили из трёх литровых банок, причем половина банки мёда осталось, потому, что не поместилось в кувшин. РЕШЕНИЕ ОБЯЗАТЕЛЬНО

Answer 1

2.

Дано:

k=50 кН/м

x=16 мм=0.016 м

Найти:

Fупр - ?

Решение:

Сила упругости:

Fупр = -kx

Fупр=-50*0.016= -0.8кН

3.

Дано:

m1=0.4 кг

V=2.5 л=0.0025 м³

p=1400 кг/м³

Найти:

Fтяж-?

m=pV=1400*0.0025=3.5 (кг) -масса мёда

Fтяж=(m+m1)g=(0.4+3.5)*9.8≈38.2 H

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p -плотность мёда (взята 1400 кг/м³,но может отличаться, надо смотреть в своём учебнике)

V-объём мёда (переведён из литров  в м³)

g=9.8 Н/кг-ускорение свободного падения (можно взять примерное значение 10 Н/кг, надо смотреть в своём учебнике)

m+m1=0.4+3.5=3.9 (кг)-масса кувшина с мёдом)

объём мёда - 1 л+ 1 л+ 1 л - 0.5л=2.5л

1 м³=1000 л ⇒ 1 л=0.001 м³

Answer 2

Finding the Force of Elasticity on the Climber

To find the force of elasticity acting on the climber, we need to use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position. Hooke's Law can be expressed as:

F = k * x

Where: - F is the force of elasticity - k is the spring constant (also known as stiffness or rigidity) - x is the displacement of the spring

In this case, the rope acts like a spring, and the displacement is given as 16 mm (or 0.016 m). The stiffness of the rope is given as 50 kN/m.

Using the formula, we can calculate the force of elasticity:

F = (50 kN/m) * (0.016 m)

Calculating this, we find:

F ≈ 0.8 kN

Therefore, the force of elasticity acting on the climber is approximately 0.8 kilonewtons (kN).

Determining the Force of Gravity on the Honey Jar

To determine the force of gravity acting on the honey jar, we need to consider the mass of the jar and the honey. The force of gravity can be calculated using the formula:

F = m * g

Where: - F is the force of gravity - m is the mass of the object - g is the acceleration due to gravity (approximately 9.8 m/s² on Earth)

In this case, the mass of the jar is given as 0.4 kg. The honey was poured into the jar from three-liter jars, with half of the honey remaining in the jar.

To calculate the mass of the honey, we need to know the density of honey. The density of honey can vary, but on average, it is around 1.36 kg/L.

Since half of the honey from a three-liter jar remained in the jar, the mass of the honey in the jar is:

mass of honey = (1.36 kg/L) * (1.5 L)

Calculating this, we find:

mass of honey ≈ 2.04 kg

Now, we can calculate the force of gravity:

F = (0.4 kg + 2.04 kg) * 9.8 m/s²

Calculating this, we find:

F ≈ 22.35 N

Therefore, the force of gravity acting on the honey jar is approximately 22.35 newtons (N).

I hope this helps! Let me know if you have any further questions.