Question

Дан кусок льда, массой 100 г при температуре -10 °С. Удельная теплоемкость льда 2100 Дж/(кг °С), удельная теплота плавления льда 3,34 кДж/кг. Температура плавления льда 0 °С а) определите количество теплоты, необходимое для нагревания льда до температуры плавления б) определите количество теплоты, необходимое для нагревания льда, взятого при температуре плавления

Answer 1

Ответ:

Объяснение:

Дано:

m = 100 г = 0,100 кг

t₁ = -10⁰C

с = 2 100 Дж/(кг·°С)

λ = 3,34*10⁵ Дж/кг   (Внимание! В условии ошибка!)

t₂ = 0°C

_______________

Q₁ - ?

Q₂ - ?

1)

Нагреваем лед:

Q₁ = c*m*(t₂ - t₁) = 2100*0,100*(0 - (-10)) = 2 100 Дж

2)

Плавим лед:

Q₂ = λ*m = 3,34*10⁵*0,100 = 33 400 Дж

Answer 2

Calculation of the heat required to heat the ice to its melting temperature:

To determine the amount of heat required to heat the ice from -10 °C to its melting temperature of 0 °C, we can use the formula:

Q = m * c * ΔT

Where: - Q is the heat energy (in Joules) - m is the mass of the ice (in kilograms) - c is the specific heat capacity of ice (in Joules per kilogram per degree Celsius) - ΔT is the change in temperature (in degrees Celsius)

Given: - Mass of the ice (m) = 100 g = 0.1 kg - Specific heat capacity of ice (c) = 2100 J/(kg °C) - Change in temperature (ΔT) = 0 °C - (-10 °C) = 10 °C

Substituting the values into the formula:

Q = 0.1 kg * 2100 J/(kg °C) * 10 °C

Calculating the result:

Q = 2100 J/°C * 10 °C = 21,000 J

Therefore, the amount of heat required to heat the ice from -10 °C to its melting temperature of 0 °C is 21,000 Joules.

Calculation of the heat required to melt the ice at its melting temperature:

To determine the amount of heat required to melt the ice at its melting temperature of 0 °C, we can use the formula:

Q = m * L

Where: - Q is the heat energy (in Joules) - m is the mass of the ice (in kilograms) - L is the specific latent heat of fusion of ice (in Joules per kilogram)

Given: - Mass of the ice (m) = 100 g = 0.1 kg - Specific latent heat of fusion of ice (L) = 3.34 kJ/kg = 3.34 * 10^3 J/kg

Substituting the values into the formula:

Q = 0.1 kg * 3.34 * 10^3 J/kg

Calculating the result:

Q = 334 J

Therefore, the amount of heat required to melt the ice at its melting temperature of 0 °C is 334 Joules. Please let me know if there's anything else I can help you with!