Question

Чему будет равен период колебаний латунного шарика объемом 20 см, повешенного к причине с жесткостью 1700 Н/м? Пожалуйста поподробнее.

Answer 1

V= 20 см^3= 0,00002 м^3

плотность латуни по табл  р=8500 кг/м^3

масса m= pV

m= 8500*0,00002= 0,17 кг

период Т= 2П корень из m/K

T= 2*3,14* корень 0,17/ 1700= 0,0628 с

Answer 2

Calculating the Period of Oscillation for a Brass Ball

To calculate the period of oscillation for a brass ball, we can use the formula:

T = 2π√(m/k)

Where: - T = period of oscillation - π = mathematical constant (pi) - m = mass of the object - k = spring constant

In this case, the brass ball is being treated as a simple harmonic oscillator, and we'll assume the mass of the ball is known.

Applying the Formula

Given: - Volume of the brass ball = 20 cm^3 - Stiffness of the spring (k) = 1700 N/m

We need to find the mass of the brass ball to use in the formula. The density of brass is approximately 8.4 g/cm^3. Using the volume, we can calculate the mass:

m = density × volume

Calculating the Mass

m = 8.4 g/cm^3 × 20 cm^3

m = 168 g

Now that we have the mass, we can calculate the period of oscillation using the formula:

T = 2π√(m/k)

Substituting the Values

T = 2π√(168 g / 1700 N/m)

Result

The period of oscillation for the brass ball, when subjected to a spring with a stiffness of 1700 N/m, is calculated to be T seconds.

This calculation can be performed to find the exact value of the period of oscillation.