Question

В алюминиевой кастрюле массой 600 г вскипятили молоко массой 500 г. Начальная температура кастрюли и молока равна 20 "С. A) Определите, какое количество теплоты было затрачено на нагревание кастрюли, если удельная теплоемкость алюминия равна 920 Дж/кг.°С Б)Определите, сколько энергии было затрачено для того, чтобы нагреть молоко до температуры кипения (удельная теплоемкость молока 3940 Дж/кг.°С, температура кипения молока 100 °C) B) Вычислите общее количество теплоты

Answer 1

Ответ:

Объяснение:

Ответ:

Общее колл. теплотыQ=201760Дж

Объяснение:

масса ал.кастрюли m1=0.6кг,   t1=20,  t3=100град.

масса молока  m2=0.5кг,     t2=20,   t3=100град.

Q=Q1+Q2

Q1=cm1*Δt=920*0.6*80=44160Дж,

Q2=cm2*Δt=3940*0.5*80=157600Дж,

Q=201760 Дж;

Answer 2

Answer in detail. In an aluminum pot with a mass of 600 g, milk with a mass of 500 g was boiled. The initial temperature of the pot and milk is 20 °C. A) Determine how much heat was spent on heating the pot, if the specific heat capacity of aluminum is 920 J / kg. ° C B) Determine how much energy was spent to heat the milk to the boiling point (the specific heat capacity of milk is 3940 J / kg. ° C, the boiling point of milk is 100 °C) B) Calculate the total amount of heat

To answer this question, we need to use the formula for the amount of heat Q = mcΔT, where m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

A) To find the amount of heat spent on heating the pot, we need to plug in the given values into the formula:

Q = mcΔT Q = 600 g * 920 J/kg.°C * (100 °C - 20 °C) Q = 55200000 J

Therefore, the amount of heat spent on heating the pot is 55200000 J.

B) To find the amount of energy spent to heat the milk to the boiling point, we need to do the same thing:

Q = mcΔT Q = 500 g * 3940 J/kg.°C * (100 °C - 20 °C) Q = 157000000 J

Therefore, the amount of energy spent to heat the milk to the boiling point is 157000000 J.

B) To find the total amount of heat, we need to add up the heat spent on heating the pot and the milk:

Q_total = Q_pot + Q_milk Q_total = 55200000 J + 157000000 J Q_total = 212200000 J

Therefore, the total amount of heat is 212200000 J.