Question

Тело массой 4 кг движется со скоростью 0,5 м/с и налетает на тело массой 2кг. В результате неупругого удара скорость тела стала 0,3 м/с . Чему равен импульс тела ?С какой скоростью двигалось второе тело ?Куда была направлена скорость ?

Answer 1

В общем, нужно разместить ось OX, тело 1 будет двигаться вдоль этой оси. Предположим, тело 2 двигается против этой оси, тогда:
m1v1-m2v2=(m2+m1)*v'
2-2*x=6*0.3
2x=2-1.8
2x=0.2
x=0.1. Раз нет минуса, значит, с направлением мы угадали, тело 2 двигалось против оси OX со скоростью 0.1 м/c

Ответ:
Импульс тела 1 до столкновения был равен p1=m1v1= 2кг*м/c
Импульс тела 2 до столкновения был равен p2=m2v2=0.2кг*м/c
Импульс тел после столкновения стал равен p'=(m1+m2)*v'= 0.3*6= 1.8 кг*м/c
Вектор скорости тела 2 был антинаправлен вектору скорости тела 1. Тело 2 двигалось со скоростью 0.1 м/c

Answer 2

Calculation of the momentum of the body

To calculate the momentum of the body, we can use the formula:

Momentum (p) = mass (m) × velocity (v)

Given that the mass of the body is 4 kg and the velocity is 0.5 m/s, we can calculate the initial momentum of the body:

Initial momentum = 4 kg × 0.5 m/s = 2 kg·m/s.

Calculation of the final velocity of the second body

To calculate the final velocity of the second body after the collision, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

Let's assume the initial velocity of the second body is v2. The mass of the second body is given as 2 kg. The initial momentum of the second body is:

Initial momentum of the second body = mass of the second body × initial velocity of the second body = 2 kg × v2.

After the collision, the final velocity of the second body is given as 0.3 m/s. Therefore, the final momentum of the second body is:

Final momentum of the second body = mass of the second body × final velocity of the second body = 2 kg × 0.3 m/s.

According to the principle of conservation of momentum, the initial momentum of the system (2 kg·m/s) is equal to the sum of the final momenta of the two bodies:

Initial momentum of the system = Final momentum of the first body + Final momentum of the second body.

Substituting the values, we can solve for v2:

2 kg·m/s = 2 kg × 0.3 m/s + 2 kg × v2.

Simplifying the equation:

2 kg·m/s = 0.6 kg·m/s + 2 kg × v2.

1.4 kg·m/s = 2 kg × v2.

v2 = 1.4 kg·m/s / 2 kg.

v2 = 0.7 m/s.

Direction of the velocity

The direction of the velocity can be determined based on the context of the problem. Since the problem does not provide any specific information about the direction, we cannot determine the direction of the velocity based on the given information alone. Additional information is needed to determine the direction of the velocity.