Question

КПД двигателя мотоцикла равен 25%.Сжигая 10г. бензина.Какую полезную работу совершит мотоцикл? Помогите решить)Пожалуйста полное решение.Буду благодарен.

Answer 1

$\eta= \frac{A_\Pi}{A_3}*100= \frac{A_\Pi}{qm}*100;\ A_\Pi= \frac{\eta qm}{100} = \frac{25*4,6*10^7*0,01}{100}=115000$ (Дж) $=115$ кДж

Answer 2

Calculation of Useful Work

To calculate the useful work performed by the motorcycle, we need to use the efficiency (η) of the engine and the amount of fuel burned.

Given: - Efficiency (η) of the engine = 25% - Amount of fuel burned = 10g

To find the useful work, we can use the formula:

Useful Work = Efficiency * Energy Content of Fuel

The energy content of gasoline is approximately 31,536,000 J/kg Since we have 10g of fuel burned, we need to convert it to kilograms by dividing by 1000:

Energy Content of Fuel = 10g * (1 kg / 1000g) * 31,536,000 J/kg

Now we can calculate the useful work:

Useful Work = 0.25 * (10g * (1 kg / 1000g) * 31,536,000 J/kg)

Simplifying the equation:

Useful Work = 0.25 * 10 * 31,536,000 J

Calculating the result:

Useful Work = 7,884,000 J

Therefore, the motorcycle will perform 7,884,000 Joules of useful work.

I hope this helps! Let me know if you have any further questions.