Question

Один моль одноатомного идеального газа нагревают на 1 градус цельсия один раз изобарно, второй - изохорно. на сколько больше энергии было передано в первом случае, чем во втором?!

Answer 1

При изохорном нагревании 1закон термодинамики Q=▲U ▲U изменение внутренней энергии ▲ U=3/2*(vR▲T)=12,5 Дж Q=12,5 Дж при изобарном нагревании Q=▲U+A A работа газа А=P▲V=vR▲T=8,3Дж Q=12,5+8,3=20,8Дж больше на 8,3Дж при изобарном нагревании.

Answer 2

Calculation of Energy Transfer in Different Cases

To calculate the difference in energy transferred in the two cases, we need to consider the specific heat capacity of the gas and the change in temperature.

In the first case, the gas is heated isobarically, which means the pressure remains constant. In the second case, the gas is heated isochorically, which means the volume remains constant.

Let's denote the specific heat capacity at constant pressure as Cp and the specific heat capacity at constant volume as Cv.

The energy transferred in the first case can be calculated using the formula:

Q1 = n * Cp * ΔT

where: - Q1 is the energy transferred in the first case, - n is the number of moles of the gas, - Cp is the specific heat capacity at constant pressure, and - ΔT is the change in temperature.

The energy transferred in the second case can be calculated using the formula:

Q2 = n * Cv * ΔT

where: - Q2 is the energy transferred in the second case, and - Cv is the specific heat capacity at constant volume.

To find the difference in energy transferred between the two cases, we can subtract Q2 from Q1:

Difference = Q1 - Q2

Now, let's calculate the difference in energy transferred.

Calculation

From the given information, we know that the gas is heated by 1 degree Celsius in both cases.

Let's assume that the gas is an ideal gas, and we have one mole of the gas.

Using the formulas mentioned above, we can calculate the energy transferred in each case.

From the search results, we can see that the specific heat capacity at constant pressure (Cp) is equal to 2 and the specific heat capacity at constant volume (Cv) is equal to 1.

Using these values, we can calculate the energy transferred in the first case:

Q1 = n * Cp * ΔT = 1 * 2 * 1 = 2 Joules

And the energy transferred in the second case:

Q2 = n * Cv * ΔT = 1 * 1 * 1 = 1 Joule

Now, let's calculate the difference in energy transferred:

Difference = Q1 - Q2 = 2 - 1 = 1 Joule

Therefore, the energy transferred in the first case is 1 Joule more than in the second case.

Please note that the specific heat capacities mentioned here are approximate values and may vary depending on the gas and conditions.