Question

V=2m^3 m= 2 кг p=3,0 •10^5 Па

Answer 1

Ответ:

вот ответ понятно. .......

Answer 2

It looks like you've provided values for volume (V), mass (m), and pressure (p). These are the variables for the ideal gas law, which is typically expressed as:

$PV = nRT$

Where:

• P is the pressure (in pascals, Pa)
• V is the volume (in cubic meters, m^3)
• n is the number of moles
• R is the universal gas constant (8.314 J/(mol·K))
• T is the absolute temperature (in kelvin, K)

You've provided values for V, m, and p, but we need to find the temperature (T). To do that, we can rearrange the ideal gas law as follows:

$T = \frac{PV}{nR}$

First, we need to calculate the number of moles (n) using the mass (m) and the molar mass of the gas. Since you haven't mentioned the gas, I'll assume it's an ideal gas with a molar mass of 2 kg/mol (which is not typical for any gas, but I'll use it for illustration):

$n = \frac{m}{\text{Molar Mass}} = \frac{2\, \text{kg}}{2\, \text{kg/mol}} = 1\, \text{mol}$

Now, you can calculate the temperature (T):

$T = \frac{3.0 \times 10^5\, \text{Pa} \times 2\, \text{m}^3}{1\, \text{mol} \times 8.314\, \text{J/(mol·K)}}$

Calculating this gives you the temperature in kelvin (K).