Question

Шар массой 100 г, движущийся прямолинейно со скоростью 6 м/с, догоняет второй шар массой 400 г, движущийся со скоростью 1 м/ c .определить скорость шаров после неупругого взаимодействия

Answer 1

дано                 СИ              Решение

m1=100г          0,1 кг            

v1=6 м/c          

m2= 400 г        0,4 кг 

v2=1 м/с

v-?

Answer 2

Calculation of the final velocity after an inelastic collision

To determine the final velocity of the two spheres after an inelastic collision, we can apply the principle of conservation of momentum. In an inelastic collision, the two objects stick together and move as a single unit after the collision.

The principle of conservation of momentum states that the total momentum before the collision is equal to the total momentum after the collision. Mathematically, this can be expressed as:

m1 * v1 + m2 * v2 = (m1 + m2) * vf

Where: - m1 and m2 are the masses of the two spheres (in kilograms) - v1 and v2 are the initial velocities of the two spheres (in meters per second) - vf is the final velocity of the combined spheres after the collision (in meters per second)

In this case, the first sphere has a mass of 100 grams (0.1 kg) and an initial velocity of 6 m/s, while the second sphere has a mass of 400 grams (0.4 kg) and an initial velocity of 1 m/s.

Plugging in the values into the equation, we get:

(0.1 kg) * (6 m/s) + (0.4 kg) * (1 m/s) = (0.1 kg + 0.4 kg) * vf

Simplifying the equation:

0.6 kg * 6 m/s + 0.4 kg * 1 m/s = 0.5 kg * vf

3.6 kg·m/s + 0.4 kg·m/s = 0.5 kg * vf

4 kg·m/s = 0.5 kg * vf

Now, we can solve for vf:

vf = (4 kg·m/s) / (0.5 kg) = 8 m/s

Therefore, the final velocity of the combined spheres after the inelastic collision is 8 m/s.

Please note that the above calculation assumes an idealized scenario of a perfectly inelastic collision, where there is no loss of kinetic energy. In reality, some kinetic energy may be lost due to factors such as friction or deformation of the objects involved in the collision.