Question

Сколько времени пассажир сидящий у окна поезда идущего со скоростью 54км/ч будет видеть проходящий мимо него встречный поезд скорость которого 36км/ч?Длинна поезда 250м

Answer 1

Кароче, классический закон сложения скоростей   V1-2=V1+V2=36+54=90км/ч
 значит 90км/ч =25м/с значит поезд будет проходить мимо наблюдателя за 250/25=10 секунд

Answer 2

Calculating the Time a Passenger Sees a Passing Train

To calculate the time a passenger sitting by the window of a train traveling at 54 km/h will see a passing train traveling at 36 km/h, we can use the following steps:

1. Calculate the Relative Speed of the Trains - The relative speed of the passing train as seen by the passenger is the sum of the speeds of the two trains. - The relative speed is given by the formula: \( \text{Relative Speed} = \text{Speed of Train 1} + \text{Speed of Train 2} \).

2. Convert the Relative Speed to m/s - To ensure consistency, it's helpful to convert the relative speed from km/h to m/s. - The conversion formula is: \( \text{Speed in m/s} = \frac{\text{Speed in km/h} \times 1000}{3600} \).

3. Calculate the Time Taken to Pass the Passenger - The time taken for the passing train to move past the passenger can be calculated using the formula: \( \text{Time} = \frac{\text{Length of Passing Train}}{\text{Relative Speed}} \).

4. Substitute the Given Values - Substitute the given values (speeds of the trains and the length of the passing train) into the formulas to calculate the time.

Calculation

Given: - Speed of the first train (the passenger's train), \( V_1 = 54 \, \text{km/h} \). - Speed of the passing train, \( V_2 = 36 \, \text{km/h} \). - Length of the passing train, \( L = 250 \, \text{m} \).

1. Calculate the Relative Speed - \( \text{Relative Speed} = 54 \, \text{km/h} + 36 \, \text{km/h} = 90 \, \text{km/h} \).

2. Convert the Relative Speed to m/s - \( \text{Relative Speed} = \frac{90 \times 1000}{3600} = 25 \, \text{m/s} \).

3. Calculate the Time Taken to Pass the Passenger - \( \text{Time} = \frac{250}{25} = 10 \, \text{s} \).

Conclusion

Therefore, the passenger sitting by the window of the train traveling at 54 km/h will see the passing train traveling at 36 km/h for approximately 10 seconds.