Question

Сколько тепла надо чтобы нагреть стальную деталь массой 50г от 20 до 50 градусов

Answer 1

50 г не единица СИ переводим в СИ, 1кг=1000г, 50г=0,05кг .
Число "с" алюминия= 920 Дж/кг градуса цельсия
Q=cm(t2-t1)
Q=920 Дж/кг градуса цельсия * 0,05кг (90градусов цельсия-40градусов цельсия)
= 46*50=2300градусов цельси

Answer 2

I can answer your question in Russian. To heat a steel part with a mass of 50 g from 20 to 50 degrees, you need to know the specific heat capacity of steel. This is the amount of heat required to raise the temperature of 1 kg of steel by 1 degree. According to some sources, the specific heat capacity of steel is about 500 J / (kg * °C) . Then, using the formula Q = c * m * (t2 - t1), where Q is the heat, c is the specific heat capacity, m is the mass, and t1 and t2 are the initial and final temperatures, we can calculate the heat needed for the steel part. Q = 500 * 0.05 * (50 - 20) = 750 J. Therefore, the answer is 750 J of heat. I hope this helps you.

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