Question

Помогите пожалуйста! Нужно сейчас! Вычислите виштовхувальну силу,которая действует на полностью погруженное в бензин тело,размеры которого 0,1 х 1 х 0,05 м.(же=10 н/кг С меня 20 баллов

Answer 1

Po=700 кг/м3    V=0.1*1*0.05=0.005 м3    Fa=?
===
Fa=po*g*V=700*10*0.005=35 H
===============

Answer 2

Calculating Buoyant Force in a Liquid

To calculate the buoyant force acting on a fully submerged object in a liquid, we can use the formula:

Buoyant force (F) = density of the liquid (ρ) * volume of the submerged part of the object (V) * acceleration due to gravity (g)

Where: - ρ = density of the liquid - V = volume of the submerged part of the object - g = acceleration due to gravity

Let's calculate the buoyant force for the given dimensions of the object submerged in gasoline.

Given Dimensions:

- Length (l) = 0.1 m - Width (w) = 1 m - Height (h) = 0.05 m - Density of gasoline (ρ) = 10 N/kg

Calculating Volume of Submerged Part (V):

The volume of the submerged part of the object can be calculated by multiplying its length, width, and height.

V = l * w * h = 0.1 m * 1 m * 0.05 m = 0.005 m³

Calculating Buoyant Force (F):

Now, we can use the formula to calculate the buoyant force.

Buoyant force (F) = ρ * V * g = 10 N/kg * 0.005 m³ * 9.81 m/s² ≈ 0.4905 N

So, the buoyant force acting on the fully submerged object in gasoline is approximately 0.4905 Newtons.