Question

Тело бросили со скоростью N=10м/с. На какую высоту оно полетело? ДАМ 20 БАЛЛОВ

Answer 1

V₀=10 м/с    найдем время подъема из формулы:
v=0                 v=v₀-gt;
g=10 м/с²        0=v₀-gt;
h-?                  gt=v₀  ⇒   t=v₀/g=10/10=1 c;
                   найдем высоту (h):
                       h=v₀t-gt²/2=10/1-10*1/2=5 м;
            Ответ: h=5 м.

Answer 2

Calculation of the Maximum Height

To determine the maximum height reached by an object thrown with an initial velocity of 10 m/s, we can use the equations of motion. One equation that relates the initial velocity, final velocity, acceleration, and displacement is:

v^2 = u^2 + 2as

Where: - v is the final velocity (which is 0 at the maximum height) - u is the initial velocity (10 m/s in this case) - a is the acceleration (which is the acceleration due to gravity, approximately -9.8 m/s^2) - s is the displacement (the height we want to find)

By substituting the known values into the equation, we can solve for s:

0^2 = 10^2 + 2(-9.8)s

Simplifying the equation:

0 = 100 - 19.6s

Rearranging the equation to solve for s:

19.6s = 100

s = 100 / 19.6

Using a calculator, we find that the maximum height reached by the object is approximately 5.1 meters.

Therefore, the object reaches a height of 5.1 meters when thrown with an initial velocity of 10 m/s.