Question

Луч падающий из воздуха под углом 45 градусов поверхности жидкости и после преломления отклоняется от первоначального направления на 15 градусов найти показатели преломления жидкости

Answer 1

Угол падения:
α = 45°
Угол преломления
β = α - 15 = 30°

Показатель преломления:
n = sin α / sin β = sin 45° / sin 30° = 0,5*√2 / 0,5 = √2 ≈ 1,4 

Answer 2

Calculation of Refractive Indices of the Liquid

To calculate the refractive indices of the liquid, we need to consider the incident angle and the angle of deviation after refraction.

Given: - Incident angle (angle of the incoming light ray) = 45 degrees - Angle of deviation (angle by which the light ray is deviated after refraction) = 15 degrees

To find the refractive indices of the liquid, we can use the formula:

Refractive index of the liquid = (sin(incident angle) / sin(angle of deviation))

Let's substitute the given values into the formula and calculate the refractive indices.

Refractive index of the liquid = (sin(45 degrees) / sin(15 degrees))

Using a scientific calculator or trigonometric tables, we can find the sine values for 45 degrees and 15 degrees:

sin(45 degrees) ≈ 0.707 sin(15 degrees) ≈ 0.259

Now, we can calculate the refractive index of the liquid:

Refractive index of the liquid ≈ 0.707 / 0.259 ≈ 2.73

Therefore, the refractive index of the liquid is approximately 2.73.

Please note that the values provided in the search results are not directly related to the given problem and do not provide the specific refractive index for the liquid in question. Therefore, we have performed the calculation based on the given information.