Question

F - 65,61н q1=900н Клr=10 см q2=?​

Answer 1

Ответ:

8,1•10-⁵ Кл.

Объяснение:

Answer 2

It seems like you have a problem involving electric charges and distances. The formula you can use to calculate the electric force between two point charges is Coulomb's law, which is given by:

$F = \frac{k \cdot |q1 \cdot q2|}{r^2}$

Where:

• $F$ is the electric force between the two charges.
• $k$ is Coulomb's constant, approximately equal to $8.99 \times 10^9 \, \text{N} \cdot \text{m}^2/\text{C}^2$.
• $q1$ and $q2$ are the magnitudes of the two point charges.
• $r$ is the distance between the charges.

In your problem:

• $q1 = 900 \, \text{nC}$ (nanoCoulombs)
• $r = 10 \, \text{cm} = 0.1 \, \text{meters}$

You are trying to find $q2$. To do that, we can rearrange Coulomb's law to solve for $q2$:

$q2 = \frac{F \cdot r^2}{k \cdot |q1|}$

Now, plug in the values:

$q2 = \frac{F \cdot (0.1 \, \text{m})^2}{(8.99 \times 10^9 \, \text{N} \cdot \text{m}^2/\text{C}^2) \cdot |900 \, \text{nC}|}$

Make sure to use consistent units throughout the calculation. Calculate the numerator first:

$F \cdot (0.1 \, \text{m})^2 = 65.61 \, \text{nN} \cdot \text{m}^2$

Now, calculate $q2$:

$q2 = \frac{65.61 \, \text{nN} \cdot \text{m}^2}{(8.99 \times 10^9 \, \text{N} \cdot \text{m}^2/\text{C}^2) \cdot 900 \, \text{nC}}$

Now, let's calculate $q2$:

$q2 = \frac{65.61 \, \text{nN} \cdot \text{m}^2}{(8.99 \times 10^9 \, \text{N} \cdot \text{m}^2/\text{C}^2) \cdot 900 \, \text{nC}}$

$q2 \approx \frac{65.61}{8.99 \times 10^9 \cdot 900} \, \text{C}$

Now, calculate this value:

$q2 \approx \frac{65.61}{8.09 \times 10^{12}} \, \text{C}$

$q2 \approx 8.12 \times 10^{-12} \, \text{C}$

So, the magnitude of $q2$ is approximately $8.12 \times 10^{-12}$ Coulombs.