Question

1)Xo=3 Vx=-4 X=X(t) 2)X=-3+0,8t Xo=? Vx=?

Answer 1

x=x0+V0x+at^2/2 следовательно x0=4m, V0x= -3m/c, a=4m/c^2  

Vx=V0x+at  

Vx=-3+4*2=-3+8=5m/c

Answer 2

It seems like you have two different problems involving position and velocity. Let's break them down one by one:

1. Problem 1: Given: Initial position, Xo = 3 Velocity, Vx = -4 Position as a function of time, X(t) = X

We can find the position X(t) at any time t using the formula: X(t) = Xo + Vx * t

Since we know X(t) and Vx, we can rearrange the formula to find Xo: Xo = X(t) - Vx * t

Substitute the values: Xo = 3 - (-4) * t Xo = 3 + 4t

2. Problem 2: Given: Position as a function of time, X(t) = -3 + 0.8t We need to find Xo and Vx.

From the expression given for X(t), we can see that: Xo = -3 (the coefficient of t is the velocity at t=0, which is Vx = -3) Vx = 0.8

So, in this case: Xo = -3 Vx = 0.8

Please double-check your question and ensure that the information provided is accurate. If there are any specific time values you want to know the positions for in either case, feel free to ask!