Question

T1 = ⅓t v1 = 10 км/ч t2 = ⅔t v2 = 72 км/ч --------------------- v ср. - ?

Answer 1

Vcp=(S1+S2)/(t1+t2)=

(10*1/3 * t  + 72*2/3 * t)/t=

t * 1/3(10+144)/t=1/3*154=51 1/3 км/ч≈51,3 км/ч  -  это ответ.

Answer 2

T1=20min
V1=10km/h
T2=40min
V2=72km/h
S1=?km. S2=?km
S1=200km
S2=2880km
Vср=(S1+S2)/(T1+T2)
Vср=(200+2880)/(10+72)
Vср=3080:82=37,5км/ч

Answer 3

To find the average velocity, we need to determine the total displacement and divide it by the total time.

Let's calculate the displacements for the two segments first:

Displacement for segment 1: s1 = v1 * t1 = 10 km/h * (1/3)t = (10/3)t km

Displacement for segment 2: s2 = v2 * t2 = 72 km/h * (2/3)t = (48/3)t km = 16t km

Now, we can find the total displacement by adding the individual displacements:

s_total = s1 + s2 = (10/3)t + 16t = (10/3)t + (48/3)t = (58/3)t km

The total time is given as t, which is also the time for the entire journey.

Now we can calculate the average velocity:

v_avg = s_total / t = ((58/3)t) / t = (58/3) km/h ≈ 19.33 km/h

Therefore, the average velocity for the entire journey is approximately 19.33 km/h.