Question

Q1=80 нКл . q2=0,4 мкКл . F=32мН ... r = ?

Answer 1

Ответ:

Дано: q1 (первый заряд) = 40 нКл (40 * 10-9 Кл); q2 (второй заряд) = -80 нКл (-80 * 10-9 Кл); F (сила электростатического взаимодействия зарядов) = 80 мкН (80 * 10-6 Н).

Постоянные: ε (диэлектрическая проницаемость керосина) = 2,1; k (коэфф. пропорциональности) = 9 * 109 Н*м2/Кл2.

Расстояние между точечными разноименными зарядами определим из закона Кулона: F = k * q1 * q2 / (ε * r2), откуда r = √(k * q1 * q2 / (F * ε)).

r = √(9 * 109 * 40 * 10-9 * 80 * 10-9 / (80 * 10-6 * 2,1)) = 0,414 м

Объяснение:

Answer 2

To find the distance (r) between two charges (q1 and q2) given the force (F) between them, you can use Coulomb's law, which states:

$F = \dfrac{k \cdot |q_1 \cdot q_2|}{r^2}$

where:

• $F$ is the force between the charges,
• $k$ is Coulomb's constant ($8.99 \times 10^9 \, \text{N m}^2/\text{C}^2$),
• $|q_1|$ and $|q_2|$ are the magnitudes of the two charges, and
• $r$ is the distance between the charges.

Given: $q_1 = 80 \, \text{nC} = 80 \times 10^{-9} \, \text{C}$ $q_2 = 0.4 \, \text{μC} = 0.4 \times 10^{-6} \, \text{C}$ $F = 32 \, \text{mN} = 32 \times 10^{-3} \, \text{N}$

Substitute these values into Coulomb's law equation:

$32 \times 10^{-3} = \dfrac{(8.99 \times 10^9) \cdot |80 \times 10^{-9} \cdot 0.4 \times 10^{-6}|}{r^2}$

Simplify:

$32 \times 10^{-3} = \dfrac{(8.99 \times 10^9) \cdot 32 \times 10^{-15}}{r^2}$

Now, solve for $r^2$:

$r^2 = \dfrac{(8.99 \times 10^9) \cdot 32 \times 10^{-15}}{32 \times 10^{-3}}$

$r^2 = \dfrac{8.99 \times 10^6}{10^5}$

$r^2 = 89.9$

Finally, find $r$ by taking the square root of both sides:

$r = \sqrt{89.9} \approx 9.48 \, \text{meters}$

So, the distance between the charges is approximately $9.48$ meters.