Question

ОЧЕНЬ СРОЧНО ДАЮ 50 БАЛЛОВ! Рух тіл вважайте рівноприскореним прямолінійним уздовж осі ОХ.1. Рівняння проекції швидкості руху мотоцикла v = 20 — 4t (усі величини задано в одиницях CI).Визначте: 1) проекцію прискорення та початкову швидкість руху мотоцикла; 2) час, через який мотоцикл зупиниться.​​

Answer 1

Ответ:

a=-4 м/с²

0=20-4*t

t=20/4=5 c

Answer 2

Problem Analysis

We are given the equation for the projection of the velocity of a motorcycle as v = 20 - 4t, where v is the velocity in CI units and t is the time. We need to determine the following: 1) The projection of the acceleration and the initial velocity of the motorcycle. 2) The time it takes for the motorcycle to come to a stop.

Solution

1) To find the projection of the acceleration, we need to differentiate the equation for velocity with respect to time. The derivative of v = 20 - 4t with respect to t is -4. Therefore, the projection of the acceleration is -4 CI/s^2.

To find the initial velocity, we can substitute t = 0 into the equation for velocity. When t = 0, v = 20 - 4(0) = 20. Therefore, the initial velocity of the motorcycle is 20 CI.

2) To find the time it takes for the motorcycle to come to a stop, we need to set the equation for velocity equal to zero and solve for t. Setting v = 0 in the equation 20 - 4t = 0, we get 4t = 20. Dividing both sides by 4, we find t = 5. Therefore, the motorcycle will come to a stop after 5 seconds.

Summary

To summarize: 1) The projection of the acceleration of the motorcycle is -4 CI/s^2 and the initial velocity is 20 CI. 2) The motorcycle will come to a stop after 5 seconds.

Please let me know if you need any further clarification or assistance!