Question

2.Грузик прикрепленный к пружине совершает гармонические колебания с амплитудой 0,1м и периодом 1,57с Определите максимальное ускорение грузика во время его движения​

Answer 1

Ответ:

1,6 м/с²

Объяснение:

A=0.1 м    T=1.57 c    a=?

===

a=A*ω²=A*(2*π/T)²=0.1*(2*3.14/1.57)²=1.6 м/с²

================================

Answer 2

Calculation of Maximum Acceleration

To determine the maximum acceleration of the mass attached to the spring, we can use the formula for simple harmonic motion:

a_max = ω^2 * A

where: - a_max is the maximum acceleration - ω is the angular frequency, given by 2π / T, where T is the period of the motion - A is the amplitude of the motion

Given that the amplitude is 0.1 m and the period is 1.57 s, we can substitute these values into the formula to calculate the maximum acceleration.

ω = 2π / T = 2π / 1.57 ≈ 3.99 rad/s

a_max = (3.99)^2 * 0.1 ≈ 1.59 m/s^2

Therefore, the maximum acceleration of the mass during its motion is approximately 1.59 m/s^2.