Question

провідник завдовжки 50 см що має опір 2Ом приєднано до джерела струму напругую 4В Визначте силу ампера що діє на провідник що розташований під кутом 30° до ліній магнітного поля індукція його дорівнює 0'5 Тл​

Answer 1

Дано: L=0,5 м; R=2 Ом; U=4 В; α=30°; В=0,5 Тл; Fa - ?

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I=U/R

Fa=I*B*L*sinα=U*B*L*sinα / R

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Fa=4 * 0,5 *0,5 * 0,5 / 2=0,25 А   -   это ответ.

sin30°=1/2.

Answer 2

To calculate the current flowing through a conductor, we can use Ohm's Law, which states that the current (I) is equal to the voltage (V) divided by the resistance (R). In this case, the conductor has a length of 50 cm and a resistance of 2 Ohms, and it is connected to a power source with a voltage of 4V.

Using Ohm's Law, we can calculate the current as follows:

I = V / R

Substituting the given values:

I = 4V / 2Ω

Simplifying the equation:

I = 2A

Therefore, the current flowing through the conductor is 2 Amperes.

Now, let's determine the force acting on the conductor that is positioned at a 30° angle to the magnetic field lines with an induction of 0.5 T.

The force (F) acting on a current-carrying conductor in a magnetic field can be calculated using the formula:

F = I * B * L * sin(θ)

Where: - F is the force - I is the current - B is the magnetic field induction - L is the length of the conductor - θ is the angle between the conductor and the magnetic field lines

Substituting the given values:

F = 2A * 0.5T * 50cm * sin(30°)

Converting the length to meters:

F = 2A * 0.5T * 0.5m * sin(30°)

Simplifying the equation:

F = 0.5N

Therefore, the force acting on the conductor is 0.5 Newtons.

Please note that the calculations provided are based on the given information and assumptions. If there are any additional factors or details that need to be considered, please let me know.