Question

1) Какое количество теплоты необходимо для нагревания стальной сковородки массой 300 г и находящейся в ней масла до температуры 200 градусов Цельсия (для приготовления курицы). Температура в комнате - 20 градусов. 2) Какое количество теплоты необходимо для нагревания 2 кг льда от температуры -70 градусов до температуры -20 градусов Цельсия? СРОЧНОООООО!!!!!

Answer 1

Ответ:

1)

c, Дж/кг*градус цельсия

150Дж/0.3кг*200градусов цельсия

9.000Дж-Сталь

340.000Дж-Масло

340.000Дж+9.000Дж=349.000Дж=349кДж

2)

Q=c*m*(t2-t1)

Q=2100*2*(-20-(-70)=210.000Дж=210кДж

Answer 2

Calculation 1: Heating a Steel Pan with Oil

To calculate the amount of heat required to heat a steel pan with oil, we need to consider the specific heat capacity of both the steel and the oil, as well as the temperature difference.

Given: - Mass of the steel pan: 300 g - Initial temperature of the oil: 200 degrees Celsius - Room temperature: 20 degrees Celsius

To calculate the heat required, we can use the formula:

Q = m * c * ΔT

Where: - Q is the heat required - m is the mass of the object - c is the specific heat capacity of the material - ΔT is the change in temperature

Let's calculate the heat required to heat the steel pan with oil.

1. Calculate the heat required to heat the steel pan: - Mass of the steel pan: 300 g - Specific heat capacity of steel: 0.49 J/g°C - Change in temperature: 200°C - 20°C = 180°C

Q1 = 300 g * 0.49 J/g°C * 180°C = 26,460 J

2. Calculate the heat required to heat the oil: - Mass of the oil: unknown (not provided) - Specific heat capacity of oil: unknown (not provided) - Change in temperature: 200°C - 20°C = 180°C

Unfortunately, the mass of the oil and its specific heat capacity are not provided, so we cannot calculate the exact heat required for the oil.

Therefore, the total heat required to heat the steel pan with oil is 26,460 J.

Calculation 2: Heating Ice

To calculate the amount of heat required to heat ice, we need to consider the specific heat capacity of ice and the temperature difference.

Given: - Mass of the ice: 2 kg - Initial temperature of the ice: -70 degrees Celsius - Final temperature: -20 degrees Celsius

To calculate the heat required, we can use the formula:

Q = m * c * ΔT

Where: - Q is the heat required - m is the mass of the object - c is the specific heat capacity of the material - ΔT is the change in temperature

Let's calculate the heat required to heat the ice.

1. Calculate the heat required to heat the ice: - Mass of the ice: 2 kg - Specific heat capacity of ice: 2.09 J/g°C - Change in temperature: -20°C - (-70°C) = 50°C

Q2 = 2,000 g * 2.09 J/g°C * 50°C = 209,000 J

Therefore, the total heat required to heat 2 kg of ice from -70 degrees Celsius to -20 degrees Celsius is 209,000 J.

Please note that the specific heat capacity values used in these calculations are approximate and may vary depending on the exact composition of the materials involved.

I hope this helps! Let me know if you have any further questions.