Question

3 бали 9. На нерухомій залізничній платформі, маса якої 16 т, встановлена гармата, з якої роблять постріл 50-кілограмовим снарядом під кутом 60° до горизонту. Траєкторія снаряда лежить у вертикальній площині, паралельній до залізничної колії. Яка швидкість снаряда під час вильоту з гармати, якщо після пострілу платформа відкотилася на 6м за 6 с? Маса гармати, яка з платформою складає одне ціле, дорівнює 3 т.​

Answer 1

Ответ:

1 М/С

Объяснение:

По формуле

Answer 2

To find the velocity of the projectile, we can use the principle of conservation of momentum. The momentum before the shot is equal to the momentum after the shot.

Given information:

- Mass of the cannon (m1) = 3 tons = 3000 kg - Mass of the platform (m2) = 16 tons = 16000 kg - Mass of the projectile (m) = 50 kg - Angle of the shot (θ) = 60° - Displacement of the platform after the shot (d) = 6 m - Time taken for the displacement (t) = 6 s

Calculating the velocity of the projectile:

1. Calculate the initial velocity of the platform (v_initial): - The platform and the cannon form a closed system, so the initial momentum is zero. - The final momentum is the sum of the momenta of the platform and the cannon. - Therefore, m1 * v_initial = -(m2 * v_initial) - Solving for v_initial, we find v_initial = 0 m/s.

2. Calculate the final velocity of the platform (v_final): - The final momentum of the system is zero, as there is no external force acting on it. - The momentum of the platform is given by m2 * v_final. - Therefore, m2 * v_final = 0 - Solving for v_final, we find v_final = 0 m/s.

3. Calculate the velocity of the projectile (v_projectile): - The momentum of the projectile is given by m * v_projectile. - The momentum before the shot is equal to the momentum after the shot. - Therefore, m1 * v_initial + m * v_projectile = m2 * v_final - Substituting the values we know, we get 3000 * 0 + 50 * v_projectile = 16000 * 0 - Solving for v_projectile, we find v_projectile = 0 m/s.

Therefore, the velocity of the projectile during its flight is 0 m/s.

Please note that the given information does not provide any information about the force applied by the cannon or any other external factors that could affect the velocity of the projectile.