Question

8. Велосипедист движется из пункта А в пункт В. а) Первые 200 секунд велосипедист двигался со скоростью 9 м/с. Определите путь, пройденный велосипедистом за это время [1] b) Последние 90 секунд велосипедист проехал со скоростью 6 м/с. Определите пройденный путь за ЭТО время [1] C) Вычислите среднюю скорость велосипедиста на всем пути. [1]​

Answer 1

Ответ: 180м; 540м; 8,07м/с

Объяснение:

S1=V1*t1=9*200=1800м

S2=V2*t2=6*90=540м

S=S1+S2=1800+540=2340м

t=t1+t2=200+90=290c

Vср=S/t=2340/290=8,07м/с

Answer 2

Calculation of the Distance Traveled by the Cyclist

a) The cyclist traveled at a speed of 9 m/s for the first 200 seconds. To determine the distance traveled during this time, we can use the formula:

Distance = Speed × Time

Substituting the given values, we have:

Distance = 9 m/s × 200 s = 1800 meters.

b) In the last 90 seconds, the cyclist traveled at a speed of 6 m/s. Using the same formula as above, we can calculate the distance traveled:

Distance = 6 m/s × 90 s = 540 meters.

c) To calculate the average speed of the cyclist over the entire distance, we need to know the total time taken and the total distance traveled. Since the time taken for each segment is given, we can add them together to find the total time:

Total Time = 200 s + 90 s = 290 seconds.

The total distance traveled is the sum of the distances calculated in parts a) and b):

Total Distance = 1800 meters + 540 meters = 2340 meters.

Using the formula for average speed:

Average Speed = Total Distance / Total Time = 2340 meters / 290 seconds ≈ 8.07 m/s.

Therefore, the average speed of the cyclist over the entire distance is approximately 8.07 m/s.

Please note that the calculations are based on the given information and may not account for other factors such as acceleration or deceleration during the journey.