Question

тело брошено под углом 40 градусов горизонту с начальной скоростью 10м/с. найти расстояние, которое пролетит тело до падения , высоту подъёма в верхней точке траектории ​

Answer 1

Ответ: L≈9,85 м, H≈2,07 м.

Объяснение:

Пусть v0 =10 м/с - начальная скорость тела и α=40° - угол к горизонту, кпод которым брошено тело. Если пренебречь сопротивлением воздуха, то искомое расстояние L=v0²*sin(2*α)/g, а высота подъёма H=v0²*sin²(α)/(2*g), где g - ускорение свободного падения. Полагая g≈10 м/с², находим L≈10²*sin(80°)/10≈9,85 м и H≈10²*sin²(40°)/(2*10)≈2,07 м.  

Answer 2

Problem Analysis

We are given the following information: - The body is thrown at an angle of 40 degrees to the horizon. - The initial velocity of the body is 10 m/s.

We need to find: 1. The distance traveled by the body before it falls. 2. The height reached at the highest point of the trajectory.

Solution

To solve this problem, we can use the equations of motion for projectile motion. The horizontal and vertical components of motion are independent of each other.

Let's start by finding the time of flight, which is the time it takes for the body to reach the ground. We can use the equation:

Time of flight (T) = (2 * initial velocity * sin(angle)) / acceleration due to gravity.

The acceleration due to gravity is approximately 9.8 m/s^2.

Substituting the given values, we have:

T = (2 * 10 * sin(40)) / 9.8.

Now, let's find the horizontal distance traveled by the body. We can use the equation:

Horizontal distance (D) = initial velocity * cos(angle) * time of flight.

Substituting the given values, we have:

D = 10 * cos(40) * T.

Finally, let's find the height reached at the highest point of the trajectory. We can use the equation:

Height (H) = (initial velocity^2 * sin^2(angle)) / (2 * acceleration due to gravity).

Substituting the given values, we have:

H = (10^2 * sin^2(40)) / (2 * 9.8).

Now, let's calculate the values.

Calculation

Using the equations mentioned above, we can calculate the values as follows:

T = (2 * 10 * sin(40)) / 9.8.

D = 10 * cos(40) * T.

H = (10^2 * sin^2(40)) / (2 * 9.8).

Result

After performing the calculations, we find that: - The time of flight is approximately T = 1.29 seconds. - The horizontal distance traveled by the body is approximately D = 8.63 meters. - The height reached at the highest point of the trajectory is approximately H = 2.08 meters.

Therefore, the body will travel approximately 8.63 meters before falling, and it will reach a height of approximately 2.08 meters at the highest point of the trajectory.

Please note that these values are approximate and may vary slightly depending on the exact calculations performed.

Let me know if there's anything else I can help you with!