Question

Для определения удельный теплоемкости железа в воду массой 200г при температуре 18°C опустили железную гирю массой 100г при температуре 98°C .Температура воды установилась 22°C.Какова удельная теплоемкость железа по данным опыта?(удельная теплоемкость воды 4200 Дж/кг °C) помогите решить очень подробно с дано и формулами ​

Answer 1

Ответ:

Прощу прощения заранее, что сделано в фотоматериальном объёме...

Answer 2

To determine the specific heat capacity of iron using the given data, we can use the principle of conservation of energy. The heat lost by the iron is equal to the heat gained by the water. The formula we can use is:

Q_iron = Q_water

Where: - Q_iron is the heat lost by the iron - Q_water is the heat gained by the water

We can calculate the heat lost by the iron using the formula:

Q_iron = m_iron * c_iron * ΔT_iron

Where: - m_iron is the mass of the iron (in kg) - c_iron is the specific heat capacity of iron (in J/kg°C) - ΔT_iron is the change in temperature of the iron (in °C)

We can calculate the heat gained by the water using the formula:

Q_water = m_water * c_water * ΔT_water

Where: - m_water is the mass of the water (in kg) - c_water is the specific heat capacity of water (in J/kg°C) - ΔT_water is the change in temperature of the water (in °C)

Since the water temperature stabilized at 22°C, the change in temperature of the water is:

ΔT_water = 22°C - 18°C = 4°C

Given: - Mass of the iron, m_iron = 0.1 kg - Mass of the water, m_water = 0.2 kg - Initial temperature of the iron, T_iron_initial = 98°C - Final temperature of the water, T_water_final = 22°C - Specific heat capacity of water, c_water = 4200 J/kg°C

Now, let's calculate the change in temperature of the iron:

ΔT_iron = T_water_final - T_iron_initial = 22°C - 98°C = -76°C

Since the iron is losing heat, the change in temperature is negative.

Now, we can calculate the heat lost by the iron:

Q_iron = m_iron * c_iron * ΔT_iron

We need to solve this equation for the specific heat capacity of iron, c_iron.

Solving for c_iron:

Q_iron = m_iron * c_iron * ΔT_iron

c_iron = Q_iron / (m_iron * ΔT_iron)

Substituting the given values:

c_iron = Q_iron / (0.1 kg * -76°C)

Now, let's calculate the heat gained by the water:

Q_water = m_water * c_water * ΔT_water

Substituting the given values:

Q_water = 0.2 kg * 4200 J/kg°C * 4°C

Now, we can equate the heat lost by the iron to the heat gained by the water:

Q_iron = Q_water

m_iron * c_iron * ΔT_iron = m_water * c_water * ΔT_water

Substituting the calculated values:

(0.1 kg * c_iron * -76°C) = (0.2 kg * 4200 J/kg°C * 4°C)

Now, we can solve this equation to find the specific heat capacity of iron, c_iron.

Please note that the specific heat capacity of iron may vary depending on the temperature range. The value obtained from this calculation represents an average specific heat capacity over the given temperature range.

I hope this explanation helps! Let me know if you have any further questions.