Question

У воду масою 20 кг за температури 30 °С поклали лід масою 1 кг, температура якого 0 °С. Яка температура t установиться в посудині?

Answer 1

Объяснение:

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Answer 2

Calculation of Final Temperature

To determine the final temperature in the vessel, we can use the principle of conservation of energy. The heat lost by the water will be equal to the heat gained by the ice.

The heat lost by the water can be calculated using the formula:

Q_lost = m_water * c_water * (T_initial - T_final)

Where: - Q_lost is the heat lost by the water - m_water is the mass of water (20 kg) - c_water is the specific heat capacity of water (4.186 J/g°C) - T_initial is the initial temperature of the water (30°C) - T_final is the final temperature of the mixture

The heat gained by the ice can be calculated using the formula:

Q_gained = m_ice * c_ice * (T_final - T_ice)

Where: - Q_gained is the heat gained by the ice - m_ice is the mass of ice (1 kg) - c_ice is the specific heat capacity of ice (2.09 J/g°C) - T_ice is the initial temperature of the ice (0°C)

Since the heat lost by the water is equal to the heat gained by the ice, we can set up the equation:

Q_lost = Q_gained

Substituting the values and rearranging the equation, we get:

m_water * c_water * (T_initial - T_final) = m_ice * c_ice * (T_final - T_ice)

Now we can solve for T_final.

Let's calculate the final temperature using the given values:

m_water = 20 kg c_water = 4.186 J/g°C T_initial = 30°C m_ice = 1 kg c_ice = 2.09 J/g°C T_ice = 0°C

Substituting these values into the equation:

20 * 4.186 * (30 - T_final) = 1 * 2.09 * (T_final - 0)

Simplifying the equation:

83.72 * (30 - T_final) = 2.09 * T_final

Expanding and rearranging the equation:

2511.6 - 83.72 * T_final = 2.09 * T_final

85.81 * T_final = 2511.6

T_final = 2511.6 / 85.81

T_final ≈ 29.24°C

Therefore, the final temperature in the vessel will be approximately 29.24°C.